5x^2+6x=104

Solution for 5x^2+6x=104 equation:

5x^2+6x=104

We move all terms to the left:

5x^2+6x-(104)=0

a = 5; b = 6; c = -104;
Δ = b2-4ac
Δ = 62-4·5·(-104)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-46}{2*5}=\frac{-52}{10}
=-5+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+46}{2*5}=\frac{40}{10}
=4
$